question_answer

The reagent  is

A)  LAH                          

B) \[HI+P\]              

C) \[NaAl{{H}_{4}}\]             

D) \[{{B}_{2}}{{H}_{6}}/{{H}_{2}}O\]

Correct Answer: D

Solution :

[d] 1. LAH reduces both ester and acid to alcohols. 2. \[HI+P\]reduces both ester and acid to alkane. 3. \[NaAl{{H}_{4}}\] reduces only ester to aldehyde and alcohol. 4. \[{{B}_{2}}{{H}_{6}}/{{H}_{2}}O\] selectively reduces acid to alcohol (although it can also reduce ester to alcohols) but acid group is reduced in the presence of ester.