JEE Main & Advanced Sample Paper JEE Main - Mock Test - 4

  • question_answer
    The locus of image of the point \[({{\lambda }^{2}},2\lambda )\] in the line mirror \[x-y+1=0\] where \[\lambda \] is a parameter is

    A)  \[4(y+1)={{(x+1)}^{2}}\]

    B) \[4(y-1)={{(x-1)}^{2}}\]

    C) \[4(y+1)={{(x-1)}^{2}}\]

    D)  \[4(y-1)={{(x+1)}^{2}}\]

    Correct Answer: D

    Solution :

    [d] Image of \[({{\lambda }^{2}},2\lambda )\] in the line mirror \[x-y+1=0\] is \[\frac{h-{{\lambda }^{2}}}{1}=\frac{k-2\lambda }{-1}=\frac{-2({{\lambda }^{2}}-2\lambda +1)}{2}\] \[\Rightarrow \,\,\,\,\,\,h+1=2\lambda \]                ....(1) and \[k={{\lambda }^{2}}+1\]             ....(2) Putting value of \[\lambda \] from (1) into (2), we get \[k-1={{\left( \frac{h+1}{2} \right)}^{2}}\] or \[4(y-1)={{(x+1)}^{2}},\] which is the required locus.


You need to login to perform this action.
You will be redirected in 3 sec spinner