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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 45

  • question_answer
    Circles drawn on the diameter as focal distance of any point lying on the parabola \[{{x}^{2}}-4x+6y+10=0\] will touch a fixed line whose equation is-

    A) \[y=2\]             

    B)        \[y=-1\]

    C) \[x+y=2\]       

    D)        \[x-y=2\]

    Correct Answer: B

    Solution :

    [b] \[x-4x+6y+10=0\] \[\Rightarrow {{(x-2)}^{2}}=-6(y+1)\] circle drawn on focal distance as diameter always touch the tangent at the vertex i.e. the line \[y+1=0~\Rightarrow y=-1\]


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