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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 45

  • question_answer
    For the reaction: \[{{H}_{2}}(g)+C{{O}_{2}}(g)CO(g)+{{H}_{2}}O(g),\]if the initial concentration of \[[{{H}_{2}}]=[C{{O}_{2}}]\] and \[x\text{ }mol/Litre\]of hydrogen is consumed at equilibrium, the correct expression of \[{{K}_{p}}\] is

    A) \[\frac{{{x}^{2}}}{{{(1-x)}^{2}}}\]   

    B)        \[\frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}}\]

    C) \[\frac{{{x}^{2}}}{{{(2+x)}^{2}}}\]

    D)        \[\frac{{{x}^{2}}}{1-{{x}^{2}}}\]

    Correct Answer: A

    Solution :

                \[{{H}_{2}}(g)+C{{O}_{2}}(g)CO(g)+{{H}_{2}}O(g)\]
    Initial conc. 1 1 0 0
    At eqm. \[(1-x)\] \[(1-x)\] \[x\] \[x\]
    \[{{K}_{P}}=\frac{{{p}_{CO}}.{{p}_{{{H}_{2}}O}}}{{{p}_{{{H}_{2}}.}}{{p}_{C{{O}_{2}}}}}=\frac{x.x}{(1-x)(1-x)}=\frac{{{x}^{2}}}{{{(1-x)}^{2}}}\]


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