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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 44

  • question_answer
    The loop ABCD is moving with velocity 'v' towards right. The magnetic field is 4T. The loop is connected to a resistance of 8 ohm. If steady current of 2 A flows in the loop then value of v if loop has a resistance of 4 ohm, (Given AB = 30cm, AD = 30 cm) is-

    A) \[\frac{50}{3}m/s\]         

    B)        \[20\text{ }m/s\]

    C) \[10\text{ }m/s\]           

    D)        \[\frac{100}{3}m/s\]

    Correct Answer: D

    Solution :

    [d] \[e=BV\ell sin\,37{}^\circ =BV\ell \frac{3}{5}\] \[e=\frac{36\,V}{50}\] \[i=\frac{e}{8+4}=2\] e=24 \[\frac{36V}{50}=24\] \[V=\frac{50\times 24}{36}\Rightarrow \frac{50\times 2}{3}\Rightarrow \frac{100}{3}\]


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