question_answer

The potential energy of a 1 kg particle free to move along tile x-axis is given by \[V(x)=\left( \frac{{{x}^{4}}}{4}-\frac{{{x}^{2}}}{2} \right)J.\] The total mechanical energy of the particle is 2 J. Then, the maximum speed (in m/s) is

Answer:

(2.12)