JEE Main & Advanced Sample Paper JEE Main - Mock Test - 43

  • question_answer
    In an electromagnetic wave in free space the root mean square value of the electric field is \[{{E}_{rms}}=6V/m.\]. The peak value of the magnetic field is :-

    A) \[2.83\times {{10}^{-8}}T\]

    B)       \[0.70\times {{10}^{-8}}T\]

    C) \[4.23\times {{10}^{-8}}T\]

    D)       \[1.41\times {{10}^{-8}}T\]

    Correct Answer: A

    Solution :

    Given,  \[{{E}_{rms}}=6V/m\] \[\frac{{{E}_{rms}}}{{{B}_{rms}}}=c\Rightarrow {{B}_{rms}}=\frac{{{E}_{rms}}}{c}\]                       ?.(i) \[{{B}_{rms}}=\frac{{{B}_{0}}}{\sqrt{2}}\Rightarrow {{B}_{0}}=\sqrt{2}{{B}_{rms}}\] \[{{B}_{0}}=\sqrt{2}\times \frac{{{E}_{rms}}}{C}\]From equation (i) \[=\frac{\sqrt{2}\times 6}{3\times {{10}^{8}}}=2.83\times {{10}^{-8}}T\]


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