question_answer

Which statement is INCORRECT?

A) and (III) are modest Bronsted base whereas (II) is not.

B) In (III) \[{{N}^{a}}\] is more basic than\[{{N}^{b}}\].

C) When (II) is protonated in the presence of a strong acid, protonation occurs at C-2.

D) All the nitrogen present in (I), (II), and (III) are \[s{{p}^{2}}\]hybridised.

Correct Answer: B

Solution :

[b] (I) (III) But (II) is not protonated, hence the statement (I) is true. In (II): So, \[{{N}^{b}}\] is more basic due to the presence of LP \[\bar{e}'s\]. Hence, the statement (2) is wrong Statement (3): Statement (3) is true.  Statement (4): Due to resonance all the N in I, II, and III is \[s{{p}^{2}},\]hybridised and hence statement (4) is CORRECT