A) \[{{H}_{2}}S{{O}_{4}},N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
B) \[N{{O}_{2}},N{{a}_{2}}S\]
C) \[{{H}_{2}}S{{O}_{4}},N{{a}_{2}}S{{O}_{4}}\]
D) \[{{H}_{2}}{{S}_{2}}{{O}_{3}},N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
Correct Answer: C
Solution :
[c] \[S+6HN{{O}_{3}}\xrightarrow{{}}\underset{(A)}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+6N{{O}_{2}}+2{{H}_{2}}O\] \[\underset{(A)}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+2NaOH\xrightarrow{{}}\underset{(B)}{\mathop{N{{a}_{2}}S{{O}_{4}}}}\,\]
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