question_answer

The freezing point of an 0.08 (m) \[NaHS{{O}_{4}}\] is \[-0.345{}^\circ C.\] Calculate the percentage of \[HSO_{4}^{-}\]ions that transfer a proton to water to form \[SO{{_{4}^{2-}}^{~}}\]ion. \[{{K}_{f}}\left( {{H}_{2}}O \right)=1.86\,mo{{l}^{-1}}\,kg\]

Answer:

65.92