JEE Main & Advanced Sample Paper JEE Main - Mock Test - 41

  • question_answer
    When   heated,   ammonium   carbamate decomposes as follows: \[N{{H}_{4}}COON{{H}_{2}}(s)\rightleftharpoons 2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] At a certain temperature, the equilibrium pressure of the system is 0.318 atm. \[{{K}_{p}}\]for the reaction is:

    A) 0.128            

    B)        0.426

    C) \[4.76\times {{10}^{-3}}\] 

    D)        \[2.24\times {{10}^{-2}}\]

    Correct Answer: C

    Solution :

    [c] \[\underset{Eq.\text{ }pressure}{\mathop{N{{H}_{4}}COON{{H}_{2}}(s)}}\,\underset{-2P}{\mathop{2N{{H}_{3}}(g)}}\,+\underset{P}{\mathop{C{{O}_{2}}(g)}}\,\] \[3P=0.318\Rightarrow P=0.106\] \[{{P}_{N{{H}_{3}}}}=2\times 0.106=0.212\] \[{{P}_{C{{O}_{3}}}}=0.106\] \[{{k}_{p}}=P_{N{{h}_{3}}}^{2}.{{P}_{C{{O}_{2}}}}=0.212\times 0.212\times 0.106\]    


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