A) \[Ba{{({{N}_{3}})}_{2}}\]
B) \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\]
C) \[N{{H}_{4}}N{{O}_{2}}\]
D) \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
[a] \[Ba{{({{N}_{3}})}_{2}}\xrightarrow{\Delta }Ba+3{{N}_{2}}\] [b] \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow{\Delta }C{{r}_{2}}{{O}_{3}}+{{N}_{2}}+4{{H}_{2}}O\] [c] \[N{{H}_{4}}N{{O}_{2}}\xrightarrow{\Delta }{{N}_{2}}+2{{H}_{2}}O\] [d] \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\xrightarrow{\Delta }2N{{H}_{3}}+{{H}_{2}}S{{O}_{4}}\] \[N{{H}_{3}}\] is evolved in case of [d].
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