A) \[29\text{ }k\Omega \]
B) \[82\text{ }k\Omega \]
C) \[108\text{ }k\Omega \]
D) \[\text{55 }k\Omega \]
Correct Answer: B
Solution :
[b] \[{{V}_{CE}}=-Ic\times 2\times {{10}^{3}}+9=4\] \[{{I}_{C}}=\frac{5\times {{10}^{-3}}}{2}\Rightarrow 2.5\times {{10}^{-3}}\] \[\beta =90=\frac{{{I}_{C}}}{{{I}_{B}}}\] \[{{I}_{\beta }}=\frac{2.5\times {{10}^{-3}}}{90}\] \[{{V}_{BE}}=-{{I}_{B}}{{R}_{B}}+3\] \[0.7+\frac{2.5\times {{10}^{-3}}}{50}{{R}_{B}}=3\] \[{{R}_{B}}=\frac{2.3\times 90}{2.5\times {{10}^{-3}}}\] \[=\frac{2.3\times 9}{25}\times {{10}^{4}}\] \[\Rightarrow \frac{2070}{25}\times {{10}^{3}}\Rightarrow 82\,k\Omega \]
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