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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 3

  • question_answer
    A mixture of 1.57 moles of \[{{N}_{2}}\] , 1.92 moles of  \[{{H}_{2}}\]  and 8.13 moles of \[N{{H}_{3}}\] is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant,  \[{{K}_{c}}\] for the reaction,  \[{{N}_{2(g)}}+3{{H}_{2(g)}}\rightleftharpoons 2N{{H}_{3(g)}}\] is  \[1.7\times {{10}^{2}}\] . Select the correct statement.

    A)  The reaction is at equilibrium.

    B)  The reaction goes in the direction of reactants.

    C)  The reaction goes in the direction of product.

    D)  None of these.

    Correct Answer: B

    Solution :

    [b]:                                            \[{{N}_{2(g)}}+3{{H}_{2(g)}}2N{{H}_{3(g)}}\]                  \[{{Q}_{c}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\] Given,                                             \[[N{{H}_{2}}]=\frac{8.13}{20}M=0.4065M;\]                                               \[[{{N}_{2}}]=\frac{1.57}{20}M=0.0785M\]                                                \[[{{H}_{2}}]=\frac{1.92}{20}M=0.096M\] \[{{Q}_{c}}=\frac{{{(0.4065M)}^{2}}}{(0.0785M){{(0.096M)}^{3}}}=2.379\times {{10}^{3}}{{M}^{-2}}\]                                                           \[{{Q}_{c}}\ne {{K}_{c}}\] , so the reaction is not in equilibrium.                                                             \[{{Q}_{c}}>{{K}_{c}}\] it indicates that the reaction will proceed in the direction of reactants.


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