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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 3

  • question_answer
    Sinusoidal carrier voltage of frequency \[1.5\text{ }MHz\] and amplitude 50 V is amplitude modulated by sinusoidal voltage of frequency 10 kHz producing 50% modulation. The lower and upper side-band frequencies in kHz are

    A) \[1490,1510\]        

    B) \[1510,1490\]

    C) \[\frac{1}{1490},\frac{1}{1510}\]          

    D) \[\frac{1}{1510},\frac{1}{1490}\]

    Correct Answer: A

    Solution :

    Here, \[{{f}_{C}}=1.5\,MHz=1500\,kHz,{{f}_{m}}=10kHz\] \[\therefore \] Low side band frequency \[={{f}_{C}}-{{f}_{m}}=1500kHz-10kHz=1490\,kHz\] Upper side band frequency \[={{f}_{C}}+{{f}_{m}}=1500kHz+10kHz=1510\,kHz\]


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