A) \[C{{H}_{3}}C{{H}_{2}}COCl\]
B) \[C{{H}_{3}}C{{H}_{2}}CHO\]
C) \[C{{H}_{2}}=CHCOOH\]
D) \[ClC{{H}_{2}}C{{H}_{2}}COOH\]
Correct Answer: C
Solution :
\[{{\operatorname{CH}}_{3}}C{{H}_{2}}COOH\,\,\xrightarrow[red\,P]{C{{l}_{2}}}\,\,C{{H}_{3}}CHClCOOH\] \[\xrightarrow[-HCl]{alc.\,KOH}C{{H}_{2}}=\underset{Acrylic\,\,acid}{\mathop{CHCOOH}}\,\]
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