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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 39

  • question_answer
    In two experiments with a continuous flow calorimeter to determine the specific heat capacity of a liquid, an input power of 60 W produced a rise of 10 K in the liquid. When the power was doubled, the same temperature rise was achieved by making the rate of flow of liquid three times faster. The power lost to the surrounding in each case was-

    A) 20 W                

    B)        30 W

    C) 40 W                

    D)        120 W

    Correct Answer: B

    Solution :

    [b] \[\Delta T=10k\] \[P=60\text{ }W\] \[P=mS\Delta T+P'\] \[60=mS\times 10+P'\] \[120=3m\times S\times 10+P'\] \[2ms\times 10=60\] \[ms\times 10=30\] hence P' = 30


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