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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 37

  • question_answer
    \[0.5g\]of fuming sulphuric acid \[({{H}_{2}}S{{O}_{4}}+S{{O}_{3}}),\]called oleum, is diluted with water. This solution completely neutralised by \[26.7mL\] of \[0.4\text{ }M\]\[NaOH\]. The percentage of free \[S{{O}_{3}}\] in the sample solution is ______.

    Answer:

    20.6


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