JEE Main & Advanced Sample Paper JEE Main - Mock Test - 37

  • question_answer
    The oscillation of a body on a smooth horizontal surface is represented by the equation,\[\operatorname{X}= A cos \left( \omega \,t \right)\] where \[X=\text{ }displacement\text{ }at\text{ }time\text{ }t\] \[\omega =frequency\text{ }of\text{ }oscillation\]Which one of the following graphs shows correctly the variation of ?a? with ?t??

    A)

    B)

    C)

    D)

    Correct Answer: C

    Solution :

    Displacement, \[\operatorname{x} = A cos \left( \omega \,t \right)\] (given) Velocity, \[\operatorname{v} = \frac{dx}{dt}=-A\omega \,\sin \,(\omega t)\] Acceleration, \[\operatorname{a} = \frac{dv}{dt} = -A{{\omega }^{2}}\,cos \omega t\] Hence graph correctly dipicts the variation of a with t.


You need to login to perform this action.
You will be redirected in 3 sec spinner