A) \[3\times 1{{0}^{8}}m/s\]
B) \[1.34\times {{10}^{8}}\,m/s\]
C) \[2.25\times {{10}^{8}}m/s\]
D) \[2.5\times {{10}^{8}}m/s\]
Correct Answer: C
Solution :
\[\mu \propto \frac{1}{\nu }\propto \frac{1}{\lambda }\] \[\therefore \,\,\,v\propto \lambda \] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\Rightarrow \frac{3\times {{10}^{8}}}{{{V}^{2}}}=\frac{633}{474}\Rightarrow {{V}_{2}}=3\times {{10}^{8}}\times \frac{474}{633}\] \[=\,\,\,2.25\times 1{{0}^{8}}m/s.\]
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