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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 34

  • question_answer
    Two students while solving a quadratic equation in x, one copied the constant term incorrectly and got the roots 3 and 2. The other copied the constant term and coefficient of \[{{x}^{2}}\] correctly as - 6 and 1 respectively. The correct roots are-

    A) 3,-2      

    B)        -3, 2  

    C) -6,-1     

    D)        6,-1

    Correct Answer: D

    Solution :

    [d] Let quadratic equation \[={{x}^{2}}+bx-6=0\] constant term = wrong             \[\Downarrow \] wrong roots = 3, 2 but sum of roots =3+2 It means, \[3+2=\frac{-b}{1}\] b = -5 correct \[\Rightarrow \]\[{{x}^{2}}-5x-6=0\] \[\left( x+1 \right)\left( x-6 \right)=0\] \[x=-1,\text{ }6\] roots


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