A) \[\frac{\sqrt{3}a}{7\pi }\]
B) \[\frac{a}{7\pi }\]
C) \[\frac{3a}{14\pi }\]
D) None of these
Correct Answer: C
Solution :
[c] \[{{a}_{avg}}=\frac{{{v}_{r}}-{{v}_{i}}}{t}=\frac{\left( \frac{\omega A}{2} \right)-\left( \omega A \right)}{\frac{7}{6}\pi }\] \[=\frac{\omega A}{2\times \frac{7}{6}\times \frac{2\pi }{\omega }}=\frac{6{{\omega }^{2}}A}{28\pi }=\frac{3}{14\pi }{{\omega }^{2}}A\] \[a={{\omega }^{2}}A\] \[{{a}_{avg}}=\frac{3a}{14\pi }\]
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