question_answer

 (at. no. of ) has a magnetic moment of 3.83 B. M. The correct distribution of 3d electrons in the central metal of the complex is

A)          

B)

C)  

D)       

Correct Answer: B

Solution :

\[\mu =\,\,\sqrt{n(n+2)}\] \[3.83 = \sqrt{n\left( n+2 \right)}\] on solving \[\operatorname{n} = 3\] as per magnetic moment, it has three impaired electron. \[{{\operatorname{Cr}}^{3}}^{+}\] will have configuration as \[\operatorname{Cr} :\,\,\,1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{4}}4{{s}^{2}}\] \[\operatorname{C}{{r}^{3+}}:\,\,1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\]