question_answer

A force acts on a \[3\text{ }g\]particle in such a way that the position of the particle as a function of time is given by \[x=3t-4{{t}^{2}}+{{t}^{3}},\]where x is in metres and t is in seconds. What is the work done (in\[mJ\]) during the first 4 second?

Answer:

528