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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 33

  • question_answer
    \[{{I}_{2}}\left( s \right)/{{I}^{-}}\left( 0.1\text{ }M \right)\] half-cell is connected to a \[{{H}^{+}}(aq)/{{H}_{2}}(1\,bar)/Pt\] half cell and e.m.f. is found to be \[0.7714\text{ }V.\text{ }If\,E_{{{I}_{2}}/{{I}^{-}}}^{{}^\circ }=0.535\text{ }V,\] find the pH of \[{{H}^{+}}/{{H}_{2}}\] half-cell.

    A) 1         

    B)                    3     

    C) 5                     

    D)        7

    Correct Answer: B

    Solution :

    [b] The cell reaction is \[{{H}_{2(g)}}+{{I}_{2(s)}}2H_{(aq)}^{+}2I_{(aq)}^{-}\] \[0.7714=0.535-\frac{0.0591}{2}log\frac{{{[{{H}^{+}}]}^{2}}{{[{{I}^{-}}]}^{2}}}{{{P}_{{{H}_{2}}}}}\] \[pH=3\]


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