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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 33

  • question_answer
    The total energy of electron in the ground state of hydrogen atom is\[-13.6\text{ }eV\]. The kinetic energy of an electron in the first excited state is

    A) \[1.7\text{ }eV\]                 

    B)       \[3.4\text{ }eV\]        

    C)   \[6.8\text{ }eV\]               

    D)        \[13.6\text{ }eV\]

    Correct Answer: B

    Solution :

    [b] Total energy in first excited state \[=-\frac{13.4}{4}=-3.4eV\] K.E. in first excited state = - total energy in that     state \[=-(-3.4)=3.4\,eV\]     


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