JEE Main & Advanced Sample Paper JEE Main - Mock Test - 31

  • question_answer
    A gas is found to obey the law \[{{P}^{2}}V\]= constant the initial temperature and volume are To and\[{{V}_{0}}\]. If the gas expands to volume\[2{{V}_{0}}\], its final temperature becomes-

    A) \[\sqrt{2}\,{{T}_{0}}\]         

    B) \[2\,{{T}_{0}}\]

    C) \[\,{{T}_{0}}/2\]            

    D)        \[\,{{T}_{0}}/\sqrt{2}\]

    Correct Answer: A

    Solution :

    [a] \[{{P}^{2}}V=constant.\Rightarrow \frac{{{T}^{2}}}{V}=constant\] \[\Rightarrow {{T}_{2}}=\sqrt{\frac{{{V}_{2}}}{{{V}_{1}}}}{{T}_{1}}=\sqrt{2}\,{{T}_{0}}\]            


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