A) phosphorous acid
B) orthophosphoric acid
C) hypophosphorous acid
D) metaphosphoric acid
Correct Answer: A
Solution :
O.N. of P in \[{{H}_{3}}P{{O}_{3}}\] (phosphorous acid) \[3x(+1)+x+3\times (-2)=0\,\,or\,\,x=+3\] In orthophosphoric acid \[\left( {{H}_{3}}P{{O}_{3}} \right)\] O.N. of P is + 5, in hypophosphorous acid \[\left( {{H}_{3}}P{{O}_{2}} \right)\] it is + 1 while in metaphosphoric acid \[(HP{{O}_{3}})\], it is + 5,
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