A) 10.8
B) 10.2
C) 11.2
D) 10.0
Correct Answer: A
Solution :
\[=\,\,\frac{R.A.(1)\times M.No+R.A.(2)\times M.No}{R.A.(1)+R.A.(2)}\] Where, \[\operatorname{R}.A. = relative abundance\] \[M.No=Mass\,\,number\] \[=\,\,\frac{19\times 10+81\times 11}{100}=10.81\]
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