A) 4
B) \[\frac{\pi }{2}\]
C) \[\frac{\pi }{2\sqrt{2}}\]
D) \[2\pi \]
Correct Answer: B
Solution :
[b] The given equation of SHM is \[2\frac{{{d}^{2}}x}{d{{t}^{2}}}+32x=0\] \[\frac{{{d}^{2}}x}{d{{t}^{2}}}+16x=0\] ??....(1) Comparing equation (1) with standard equation of SHM \[\frac{{{d}^{2}}x}{d{{t}^{2}}}+{{\omega }^{2}}x=0\] \[\omega =\sqrt{16}=4\] Time period \[T=\frac{2\pi }{\omega }=\frac{2\pi }{4}=\frac{\pi }{2}sec\]
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