question_answer

In the circuit shown, the charges on the capacitors A and B are respectively-

A) CV, CV

B)        \[\frac{CV}{2},\frac{CV}{2}\]

C) \[CV,\frac{CV}{2}\]      

D)        \[\frac{CV}{2},CV\]

Correct Answer: D

Solution :

[d] \[q={{C}_{eq}}V=CV\] \[\therefore {{q}_{B}}=CV\] \[{{q}_{A}}=\frac{CV}{2}\]