A) \[{{r}_{3}}={{r}_{1}}+{{r}_{2}}\]
B) \[{{r}_{2}}=\sqrt{{{r}_{1}}{{r}_{3}}}\]
C) \[{{r}_{2}}={{r}_{1}}+{{r}_{3}}\]
D) \[{{r}_{2}}={{r}_{3}}-{{r}_{1}}\]
Correct Answer: C
Solution :
[c] At inner surface \[V=\frac{\sigma {{r}_{1}}}{{{\in }_{0}}}+\frac{(-\sigma ){{r}_{2}}}{{{\in }_{0}}}+\frac{\sigma {{r}_{3}}}{{{\in }_{0}}}=0\] \[\frac{\sigma }{{{\in }_{0}}}\left[ {{r}_{1}}-{{r}_{2}}+{{r}_{3}} \right]=0\] \[\therefore \text{ }{{r}_{2}}={{r}_{1}}+{{r}_{3}}\]
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