A) \[0.15\]
B) \[0.4\]
C) \[0.25\]
D) \[0.6\]
Correct Answer: D
Solution :
[d] \[{{W}_{AB}}=5J\] \[\Delta {{U}_{ab}}=0\] (isothermal) \[{{Q}_{ab}}=5J\] (First law) \[{{W}_{bc}}=4J\] \[{{Q}_{bc}}=0\] (Adiabatic) \[\Delta {{U}_{bc}}=-4J\] (Adiabatic) \[\Delta {{U}_{bc}}=-4J\] (First law) \[\therefore \,\,\,\,\,\Delta {{U}_{ab}}+\Delta {{U}_{bc}}+\Delta {{U}_{ca}}=0\] \[\therefore \,\,\,\,\,\,\Delta {{U}_{ca}}=4J\] Also, \[{{W}_{ab}}+{{W}_{bc}}+{{W}_{ca}}=3J\] (Area inside cycle) \[5+4+{{W}_{ca}}=3\] First law for process ca \[{{Q}_{ca}}=4-6=-2J\] Efficiency of cycle \[\eta =\frac{{{W}_{cycle}}}{{{Q}_{ab}}}=\frac{3}{5}=0.6\]
You need to login to perform this action.
You will be redirected in
3 sec
