A) \[x=\frac{y+1}{y-1}\]
B) \[x=\frac{1-y}{y+1}\]
C) \[y=\frac{1-x}{1+x}\]
D) \[xy+x-y+1=0\]
Correct Answer: D
Solution :
[d]: We have, \[x=\frac{1-\sin \phi }{\cos \phi },y=\frac{1+\cos \phi }{\sin \phi }\] \[xy+1=\frac{1-\sin \phi +\cos \phi }{\cos \phi .\sin \phi }=-(x-y).\] Hence, \[xy+1+x-y=0\] \[\therefore \]\[x=\frac{y-1}{y+1},y=\frac{1+x}{1-x}\].
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