A) B
B) A - B
C) \[A\cap B\]
D) \[{{A}^{c}}\cap {{B}^{c}}\]
Correct Answer: C
Solution :
[c]:\[A-(A-B)=A\cap {{(A-B)}^{c}}=A\cap {{(A\cap {{B}^{c}})}^{c}}\] \[=A\cap ({{A}^{c}}\cup B)=(A\cap {{A}^{c}})\cup (A\cap B)\] [distributive law] \[=\phi \cup (A\cap B)=A\cap B\]
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