JEE Main & Advanced Sample Paper JEE Main - Mock Test - 30

  • question_answer
    The densities of graphite and diamond at 298 K are 2.25 and \[3.31 g cm{{\,}^{-3}}\], respectively. If the standard free energy difference \[(\Delta G{}^\circ )\] is equal to \[1895 J mol{{\,}^{-}}^{1}\], the pressure at which graphite will be transformed into diamond at 298 K is

    Answer:

    \[\left( 11.09\times 1{{0}^{8}} \right)\Delta G = - P\Delta V= Work done\]


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