If \[\theta =45{}^\circ \] the electric flux through the hemispherical shell is
A) Zero
B) \[\pi {{R}^{2}}E\]
C) \[\frac{\pi {{R}^{2}}E}{\sqrt{2}}\]
D) \[\sqrt{2}\,\pi {{R}^{2}}E\]
Correct Answer: C
Solution :
[c] \[=\phi =(\pi {{R}^{2}}\cos 45{}^\circ )\times E=\frac{\pi {{R}^{2}}E}{\sqrt{2}}\]
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