A) 6.00 cm
B) 7.75 cm
C) 9.25 cm
D) 11.0 cm
Correct Answer: D
Solution :
[d]: Here, \[{{f}_{0}}=1.5cm,{{f}_{e}}=6.25cm,\] \[{{u}_{0}}=-2cm,{{v}_{e}}=-25cm\] For objective, \[\frac{1}{{{v}_{0}}}-\frac{1}{{{u}_{0}}}=\frac{1}{{{f}_{0}}}\therefore \frac{1}{{{v}_{0}}}-\frac{1}{-2}=\frac{1}{1.5}\] \[\frac{1}{{{v}_{0}}}=\frac{1}{1.5}-\frac{1}{2}\]or\[{{v}_{0}}=6cm\] For eye piece, \[\frac{1}{{{v}_{e}}}-\frac{1}{{{u}_{e}}}=\frac{1}{{{f}_{e}}}\Rightarrow \frac{1}{-25}-\frac{1}{{{u}_{e}}}=\frac{1}{6.25}\] \[-\frac{1}{{{u}_{e}}}=\frac{1}{6.25}+\frac{1}{25}\]or\[{{u}_{e}}=-5cm\] Distance between two lenses\[=|{{v}_{0}}|+|{{u}_{e}}|\] \[=6cm+5cm=11cm\]
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