A) \[\frac{f-a}{2(l+b)}\]
B) \[\frac{a-1}{l\,+b}\]
C) \[\frac{a+1}{2(b-1)}\]
D) \[\frac{a+f}{2(l+b)}\]
Correct Answer: A
Solution :
\[{{V}_{p}}=\frac{d{{x}_{p}}}{dt}=a+2bt\] and \[{{V}_{Q}}=\,\,\frac{d{{x}_{Q}}}{dt}=f-2t,\,\,\,Given,\,\,{{V}_{p}}={{V}_{Q}}\,\,\] \[\therefore \,\,\,a+2bt=f-2t\,\,\,\Rightarrow \,\,t=\frac{f-a}{2(b+1)}\]You need to login to perform this action.
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