A) \[{{H}_{2}}O,N{{O}_{2}},NaCl\]
B) \[N{{H}_{3}},{{H}_{2}}O,N{{H}_{4}}N{{O}_{3}}\]
C) \[HCl,NO,N{{H}_{4}}Cl\]
D) \[C{{O}_{2}},S{{O}_{2}},N{{a}_{2}}S{{O}_{3}}\]
Correct Answer: B
Solution :
[b]: \[\underset{(A)}{\mathop{N{{H}_{4}}N{{O}_{3}}}}\,+NaOH\xrightarrow[{}]{boiling}NaN{{O}_{3}}\]\[+\underset{(B)}{\mathop{N{{H}_{3}}}}\,+{{H}_{2}}O\] \[N{{H}_{3}}\]gives brown ppt. with Nesslers reagent\[({{K}_{2}}Hg{{I}_{4}})\] \[2{{K}_{2}}[Hg{{I}_{4}}]+N{{H}_{3}}+3KOH\xrightarrow[{}]{{}}\underset{Brown\,ppt.}{\mathop{{{H}_{2}}N.HgO.HgI}}\,\]\[+7KI+{{H}_{2}}O\] [a] on heating gives \[{{N}_{2}}O\]gas [c] which rekindles a glowing splinter but is not converted into \[{{N}_{2}}O\]by air oxidation. \[\underset{(A)}{\mathop{N{{H}_{4}}N{{O}_{3}}}}\,\xrightarrow[{}]{\Delta }\underset{(C)}{\mathop{{{N}_{2}}O}}\,+2{{H}_{2}}O\]You need to login to perform this action.
You will be redirected in
3 sec