A) \[9.61\times 1{{0}^{14}}per\,sec\]
B) \[4.12 \times 1{{0}^{13}}per sec\]
C) \[1.51 \times \,1{{0}^{12}}per sec\]
D) \[2.13 \times 1{{0}^{11}}per sec\]
Correct Answer: C
Solution :
Intensity of light \[I=\frac{Watt}{Area}=\frac{nhc}{A\lambda }\Rightarrow \,\,Number\,\,of\,\,photon\,\,=\,\,\frac{IA\lambda }{hc}\] \[\therefore Number of\,\,photoelectrons emitted = \frac{1}{100}\times \frac{IA\lambda }{hc}\]\[=\,\,\frac{1}{100}\times \frac{1\times {{10}^{-\,4}}\times 300\times {{10}^{-9}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}=1.5\times {{10}^{12}}\,\,per\,\,\sec \]
You need to login to perform this action.
You will be redirected in
3 sec
