A) \[{{I}_{A}}>{{I}_{B}}\]
B) \[{{I}_{A}}={{I}_{B}}\]
C) \[{{I}_{A}}<{{I}_{B}}\]
D) Depends on the actual value of t and r
Correct Answer: C
Solution :
[c] 0\[I=\frac{m{{r}^{2}}}{2}=\rho \left( \pi {{r}^{2}}t \right)\frac{{{r}^{2}}}{2}\] \[I\propto {{r}^{4}}t\] \[\frac{{{I}_{A}}}{{{I}_{b}}}={{\left[ \frac{{{r}_{A}}}{{{r}_{B}}} \right]}^{4}}.\frac{{{t}_{A}}}{{{t}_{B}}}={{\left[ \frac{1}{4} \right]}^{4}}.\frac{4}{1}={{\left[ \frac{1}{4} \right]}^{3}}\] Hence, \[{{I}_{A}}=\frac{{{I}_{B}}}{{{4}^{3}}}\] or \[{{I}_{A}}<{{I}_{B}}\]
You need to login to perform this action.
You will be redirected in
3 sec
