JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    The coefficient of \[{{x}^{3}}\] in the expansion of \[{{(1-x+{{x}^{2}})}^{6}}\] is

    A) \[50\]                    

    B)        \[-50\]    

    C) \[68\]                    

    D)        None of these

    Correct Answer: B

    Solution :

        [b] \[{{(1-x+{{x}^{2}})}^{6}}={{[1-x(1-x)]}^{6}}\] \[{{=}^{6}}{{C}_{0}}{{-}^{6}}{{C}_{1}}x(1-x){{+}^{6}}{{C}_{2}}{{x}^{2}}{{(1-x)}^{2}}{{-}^{6}}{{C}_{3}}{{x}^{3}}{{(1-x)}^{3}}+\]???.up to 7 terms \[{{=}^{6}}{{C}_{0}}{{-}^{6}}{{C}_{1}}x(1-x){{+}^{6}}{{C}_{2}}{{x}^{2}}(1-2x+{{x}^{2}})\] \[{{-}^{6}}{{C}_{3}}{{x}^{3}}(1-3x+3{{x}^{2}}-{{x}^{3}})+\]... up to 7 terms \[\therefore \]  Coefficient of \[{{x}^{3}}=-2{{\times }^{6}}{{C}_{2}}{{-}^{6}}{{C}_{3}}\] \[=-2\frac{6!}{2!4!}-\frac{6!}{3!3!}=-50\]          


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