JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    The mean and variance of a binomial distribution are 30 and 5, respectively. Then probability of two successes is

    A) \[\frac{875}{{{6}^{34}}}\]      

    B)        \[\frac{875}{2\times {{6}^{34}}}\]

    C) \[^{36}{{C}_{2}}{{\left( \frac{5}{6} \right)}^{36}}\]  

    D)        \[^{36}{{C}_{2}}{{\left( \frac{5}{6} \right)}^{34}}{{\left( \frac{1}{6} \right)}^{2}}\]

    Correct Answer: B

    Solution :

    [b] \[np=30,\,\,npq=5\] \[q=\frac{1}{6},\,\,p=\frac{5}{6}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,n=36\] Required probability \[{{=}^{36}}{{C}_{2}}{{\left( \frac{1}{6} \right)}^{34}}{{\left( \frac{5}{6} \right)}^{2}}\] \[=\frac{36\times 35}{2}\frac{25}{{{6}^{34}}\times 36}=\frac{875}{2\times {{6}^{34}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner