A) \[m=\frac{It}{(63.5\times 96500)}\]
B) \[m=\frac{It}{(31.25\times 96500)}\]
C) \[m=\frac{I\times 96500}{(31.25\times t)}\]
D) \[m=\frac{31.75\times I\times t}{96500}\]
Correct Answer: D
Solution :
[d]: According to Faraday's law of electrolysis \[m\propto It\]or \[m=ZIt\]where I = current, t = time \[Z=\frac{\text{Equivalent weight of substance}}{\text{96500}}\] Eq. wt. of \[Cu=\frac{63.5}{2}\] \[(\because C{{u}^{2+}}\to Cu)\] \[Z=\frac{63.5}{2\times 96500}\] \[\therefore \]\[m=\frac{63.5\times I\times t}{2\times 96500}=\frac{31.75\times I\times t}{96500}\]
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