JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    Which of the following arrangements is correct in respect of solubility in water?

    A) \[CaS{{O}_{4}}>BaS{{O}_{4}}>BeS{{O}_{4}}>MgS{{O}_{4}}>SrS{{O}_{4}}\]

    B) \[BeS{{O}_{4}}>MgS{{O}_{4}}>CaS{{O}_{4}}>SrS{{O}_{4}}\]\[>BaS{{O}_{4}}\]

    C) \[BaS{{O}_{4}}>SrS{{O}_{4}}>CaS{{O}_{4}}>MgS{{O}_{4}}\]\[>BaS{{O}_{4}}\]

    D) \[BeS{{O}_{4}}>CaS{{O}_{4}}>MgS{{O}_{4}}>SrS{{O}_{4}}\]\[>BaS{{O}_{4}}\]

    Correct Answer: B

    Solution :

    [b]: The solubilities of sulphates of alkaline earth metals decrease down the group because the hydration enthalpy decreases from \[B{{e}^{2+}}\]to \[B{{a}^{2+}}\]appreciably as the size of the cation increases. As the sulphate ion is too big, the magnitude of lattice enthalpy almost remains constant on moving down the group. So, the correct order of solubility in water is \[BeS{{O}_{4}}>MgS{{O}_{4}}>CaS{{O}_{4}}>SrS{{O}_{4}}>BaS{{O}_{4}}.\]


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