A) \[+1,+1,\sqrt{15\,}BM.\]
B) \[+2,+1,\sqrt{15\,}\,BM.\]
C) \[+2,+1,\sqrt{35\,}\,BM.\]
D) \[+1,0,\sqrt{35\,}\,BM.\]
Correct Answer: A
Solution :
[a] Complex (X) is: \[{{\left[ \overset{+1}{\mathop{Fe}}\,{{({{H}_{2}}O)}_{5}}N{{O}^{\oplus }} \right]}^{2+}}.S{{O}_{4}}^{2-}\] It has 3 unpaired \[\bar{e}'s\]. So \[{{\mu }_{MM}}=\sqrt{n(n+2)}=\sqrt{3(3+3)}=\sqrt{15}BM\]
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