A) \[{{\left[ Ni{{(en)}_{3}} \right]}^{2+}}\]
B) \[{{\left[ Ni{{(N{{H}_{3}})}_{4}}{{({{H}_{2}}O)}_{2}} \right]}^{2+}}\]
C) \[\left[ Pt\,{{(N{{H}_{3}})}_{2}}C{{l}_{2}} \right]\]
D) \[\left[ Ni\,{{\left( N{{H}_{3}} \right)}_{2}}C{{l}_{2}} \right]\]
Correct Answer: D
Solution :
In \[\left[ Ni{{\left( N{{H}_{3}} \right)}_{2}}C{{l}_{2}} \right],\] \[N{{i}^{2+}}\] is in \[s{{p}^{3}}\]hybridisation, thus tetrahedral in shape. Hence the four ligands are not different to exhibit optical isomerism. In tetrahedral geometry all the positions are adjacent to one another, therefore, geometrical isomerism is not possible.
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