| (I) \[K{{O}_{2}}\] |
| (II) \[{{O}_{2}}[As{{F}_{6}}]\] |
| (III) \[{{O}_{2}}\] |
| (IV) \[N{{a}_{2}}{{O}_{2}}\] |
A) \[IV>I>III>II\]
B) \[II>III>I>IV\]
C) \[I>III>IV>II\]
D) \[III>II>IV>I\]
Correct Answer: A
Solution :
[a] (I) \[K{{O}_{2}}\] has \[{{O}_{2}}^{\Theta }\] (superoxide ion). Bond order \[=1.5\] (II) \[{{O}_{2}}[As{{F}_{6}}]\] has \[{{O}_{2}}^{\oplus }\] (Dioxygenyl ion). Bond order \[=2.5\] (III) \[{{O}_{2}},\] Bond order = 2 (IV) \[N{{a}_{2}}{{O}_{2}}\]has \[{{O}_{2}}^{2-}\] (peroxide ion). Bond order = 1 Higher the B.O, smaller is the bond length Hence order of bond length is: \[IV>I>III>II\] (i.e,. \[{{O}_{2}}^{2-}>{{O}_{2}}^{\Theta }>{{O}_{2}}>{{O}_{2}}^{\oplus }\])
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