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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 1

  • question_answer
    The dissociation constant of two acids \[H{{A}_{1}}\]and \[H{{A}_{2}}\] are \[3.14\times {{10}^{-4}}\] and \[1.96\times {{10}^{-5}}\] respectively The relative strength of the acids will be approximately

    A) \[1:4\]               

    B) \[4:1\]   

    C) \[1:16\]             

    D) \[16:1\]

    Correct Answer: B

    Solution :

    \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\sqrt{\frac{{{K}_{{{a}_{1}}}}}{{{K}_{{{a}_{2}}}}}}=\sqrt{\frac{3.14\times {{10}^{-4}}}{1.96\times {{10}^{-5}}}}=4:1\]


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